A vendor hangs an 8.8kg sign in front of his shop with a cable held away from th
ID: 1285878 • Letter: A
Question
A vendor hangs an 8.8kg sign in front of his shop with a cable held away from the building by a lightweight pole. The pole is free to pivot about the end where it touches the wall, as shown in (Figure 1) .
What is the tension in the cable?
Express your answer to two significant figures and include the appropriate units.
A vendor hangs an 8.8kg sign in front of his shop with a cable held away from the building by a lightweight pole. The pole is free to pivot about the end where it touches the wall, as shown in (Figure 1) . What is the tension in the cable? Express your answer to two significant figures and include the appropriate units.Explanation / Answer
The net torque exerted on the system is zero when it is in static equilibrium.
Hence,
mgL = Tcos60oL
Thus, the tension in the cable is,
T = mg / cos60o
= (8.2 kg)(9.8 m/s2) / cos60o
= 160.72 N