Consider the following two-step process. Heat is allowed to flow out of an ideal
ID: 1286471 • Letter: C
Question
Consider the following two-step process. Heat is allowed to flow out of an ideal gas at constant volume so that its pressure drops from 2.2 atm to 1.4 atm. Then the gas expands at constant pressure, from a volume of 5.9 L to 9.3 L, where the temperature reaches its original value. (See figure(Figure 1) ).
Part A
Calculate the total work done by the gas in the process.
Express your answer using two significant figures.
Part B
Calculate the change in internal energy of the gas in the process.
Part C
Calculate the total heat flow into or out of the gas.
Express your answer using two significant figures.
Consider the following two - step process. Heat is allowed to flow out of an ideal gas at constant volume so that its pressure drops from 2.2 atm to 1.4 atm. Then the gas expands at constant pressure, from a volume of 5.9 L to 9.3 L, where the temperature reaches its original value. (See figure(Figure 1) ). Part A Calculate the total work done by the gas in the process. Express your answer using two significant figures. Part B Calculate the change in internal energy of the gas in the process. Part C Calculate the total heat flow into or out of the gas. Express your answer using two significant figures.Explanation / Answer
(A) Work Done = Area below the graph
W = 1.4 Atm x ( 9.3 L - 5.9 L ) = 1.4 x (1.01 x 105 Pa )x (3.4 x 10-3 m3 ) = 4.8 x 102 J Answer
(B) Since Initial and Final Temperature are same, therefore there is no Change in Internal Energy
Answer : Zero
(C) Using formula , Q = Delta U + W,
Q = W = 4.8 x 102 J Answer