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An infinitely long wire carries a current of 2 A as shown in the picture. It is

ID: 1287646 • Letter: A

Question

An infinitely long wire carries a current of 2 A as shown in the picture. It is surrounded by a hollow conducting cylinder of inner radius R1 = 2 cm and outer radius R2 3 cm that carries a uniform current of 2 A in the opposite direction.

Using Amperes law:

(a) Find the magnitude of the magnetic field B at a distance r = 1 cm from the axis of the cylinder.

(b) Find the magnitude of the magnetic field B at a distance r = 2.5 cm from the axis of the cylinder.

(c) Find the magnitude of the magnetic field B at a distance r = 4 cm from the axis of the cylinder.

An infinitely long wire carries a current of 2 A as shown in the picture. It is surrounded by a hollow conducting cylinder of inner radius R1 = 2 cm and outer radius R2 3 cm that carries a uniform current of 2 A in the opposite direction. Using Ampere s law: (a) Find the magnitude of the magnetic field B at a distance r = 1 cm from the axis of the cylinder. (b) Find the magnitude of the magnetic field B at a distance r = 2.5 cm from the axis of the cylinder. (c) Find the magnitude of the magnetic field B at a distance r = 4 cm from the axis of the cylinder.

Explanation / Answer

let I1 = 2 A

I2 = 2A

a) at r = 1 cm

I_enclosed = I1

= 2A

According to Ampere's law,

integral B.dl = mue*I_enclosed

B*2*pi*r = mue*I1

B = mue*I1/(2*pi*r)

= 4*pi*10^-7*2/(2*pi*0.01)

= 4*10^-5 T <<<<<<----------Answer

b) at r = 2.5 cm

I_enclosed = I1 - I2*pi*(R2^2 - r^2)/(pi*(R2^2-R1^2)

= 2 - 2*(0.03^2 - 0.025^2/(0.03^2-0.02^2)

= 0.9 A

integral B.dl = mue*I_enclosed

B*2*pi*r = mue*I_elcosed

B = mue*I_enclosed/(2*pi*r)

= 4*pi*10^-7*0.9/(2*pi*0.01)

= 1.8*10^-5 T <<<<<<----------Answer


c) at r = 4 cm

I_enclosed = I1 - I2

= 0

so, B = 0 <<<<<<----------Answer