An object with mass 2.1kg is executing simple harmonic motion, attached to a spr

Question

An object with mass 2.1kg is executing simple harmonic motion, attached to a spring with spring constant 300N/m. When the object is 0.020m from its equilibrium position, it is moving with a speed of 0.50m/s
Part A: calculate the amplitude of the motion.
Part B: calculate the maximum speed attained by the object. An object with mass 2.1kg is executing simple harmonic motion, attached to a spring with spring constant 300N/m. When the object is 0.020m from its equilibrium position, it is moving with a speed of 0.50m/s
Part A: calculate the amplitude of the motion.
Part B: calculate the maximum speed attained by the object.
Part A: calculate the amplitude of the motion.
Part B: calculate the maximum speed attained by the object.

Explanation / Answer

a)

(1/2) k A ^2 = (1/2) kx^2 + (1/ 2 ) m v^2

k A ^2 = k x^2 + m v^2

= ( 300 N /m )(0.02 m ) ^2 + ( 2.1 kg ) (0.5 m/s ) ^2

A = 0.0463 m

b)

Maximum speed

v = ( k /m ) ^ (1/2) A

= ( 300 N /m / ( 2.1 kg ) ^ (1/2) ( 0.0463 m )

=0.55 m/s

  

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