What is the induced charge on the faces of the glass dielectric plate? What is t

Question

What is the induced charge on the faces of the glass dielectric plate?

What is the electric field in the air between the capacitor plates?

What is the electric field in the glass between the capacitor plates?

The capacitor shown in the figure above is connected to a battery with V = 90 V. Assume a = 3.46 mm, b = 2.07 mm, A = 1.79 m2, and the dielectric constant K = 5.10. What is the magnitude of the free charge on the capacitor plates? What is the induced charge on the faces of the glass dielectric plate? What is the electric field in the air between the capacitor plates? What is the electric field in the glass between the capacitor plates?

Explanation / Answer

First calculate the capacitance. Look at it as 2 different caps in series.

C1 = (1)(8.854e-12)(1.92) / (0.00338)
C2 = (5.4)(8.854e-12)(1.92) / (0.00216)

then calculate Ct = C1

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