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In the figure below, two springs are attached to a block that can oscillate over

ID: 1298155 • Letter: I

Question

In the figure below, two springs are attached to a block that can oscillate over a floor. If the left spring is removed, the block oscillates at a frequency of 26 Hz. If, instead, the spring on the right is removed, the block oscillates at a frequency of 40 Hz. At what frequency does the block oscillate with both springs attached?

In the figure below, two springs are attached to a block that can oscillate over a floor. If the left spring is removed, the block oscillates at a frequency of 26 Hz. If, instead, the spring on the right is removed, the block oscillates at a frequency of 40 Hz. At what frequency does the block oscillate with both springs attached?

Explanation / Answer


initially for the left spring

w1=2pif1=sqrt(k1/m)

w1^2=k1/m

===>

k1=m*W1^2

and for the right spring

w2^2=2pif2=k1/m

===>

k2=m*W2^2

now

these two spring are attached in parallel combination

effective spring constant is k'=k1+k2

now

frequency f=1/2pi*sqrt(k'/m)

=1/2pi*sqrt(k1+k2/m)

=1/2pi*sqrt(m*W1^2+m*W2^2/m)

=1/2pi*sqrt(m*(W1^2+W2^2)/m)

=1/2pi*sqrt(W1^2+m*W2^2)

=1/2pi*sqrt((2pi*f1)^2+(2pi*f2)^2)

=1/2pi*2pi*sqrt(f1^2+f2^2)

=sqrt(f1^2+f2^2)

=sqrt(26^2+40^2)

=47.7074 Hz........is answer