Part A: A block attached to a spring with unknown spring constant oscillates wit
ID: 1301201 • Letter: P
Question
Part A:
A block attached to a spring with unknown spring constant oscillates with a period of 3.6 s. What is the period of the following?
(a) The mass is doubled?
s
(b) The mass is halved?
s
(c) The amplitude is doubled?
s
(d) The spring constant is doubled?
s
Part B:
(a) When the displacement of a mass on a spring is one-fourth of A, what fraction of the energy is kinetic energy and what fraction is potential energy?
(b) At what displacement, as a fraction of A, is the energy one-sixteenth kinetic and fifteen-sixteenths potential?
? A
Part C:
A spring with spring constant k is suspended vertically from a support and a mass m is attached. The mass is held at the point where the spring is not stretched. Then the mass is released and begins to oscillate. The lowest point in the oscillation is 38 cm below the point where the mass was released. What is the oscillation frequency?
Hz
Part D:
The two blocks in the figure below oscillate on a frictionless surface with a period of 3.9 s. The upper block just begins to slip when the amplitude is increased to 46 cm. What is the coefficient of static friction between the two blocks?
kinetic % potential %Explanation / Answer
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1. A block attached to a spring withan unknown spring constant oscillates with a period of 4.0 s. What is the period if:
a. A.The mass is doubled?
b. B.The mass is halved?
c. C.The amplitude isdoubled?
d. D.The spring constant is doubled?
Ans
Equation: T = 2??(m/k)
a) Ta= 2??(2m/k) => ?2(2??(m/k)) => ?2 T0 = 4?2.
b) Tb = 2??(m/2k) =>(1/?2)(2??(m/k)) => 1/?2 T0=> 4/?2
c) Amplitude has no impact on the period. So it just equals 4.
d) If the spring constant is doubled, the equation is the same asb, so it is again 4/?2.