In the circuits shown above, a battery with a voltage ?V bat is connected to the

Question

In the circuits shown above, a battery with a voltage ?Vbat is connected to the circuit with resistances R1, R2, and R3, and a switch connected to R3. In the circuit on the left, the switch is open and in the circuit on the right the switch is closed.

For which circuit, if either, will the voltage read by the volt meter be largest?

Question 3 options:

• Switch Closed (Right), because the total current is larger for this circuit

• Switch Open (Left), because the total current is larger for this circuit

• The voltages are the same because when the switch is closed the resistance decreaseas and the current increases

• Switch Closed (Right), because the total resistance is larger for this circuit

• Switch Open (Left), because the current is the same in both circuits and the resistance connected to the voltmeter is larger for this circuit

• Switch Closed (Right), because the current is the same in both circuits and the resistance connected to the voltmeter is larger for this circuit

• Switch Open (Left), because the battery voltage is larger for this circuit

• Switch Closed (Right), because the battery voltage is larger for this circuit

• Switch Open (Left), because the total resistance is larger for this circuit

• The voltages are the same because R2 and R3 are in parallel

• The voltages are the same because when the switch is closed the resistance increases and the current decreases

Explanation / Answer

answer is the left one.... voltage difference across R2 is larger because total resistance for left one is more than right one....take R1, R2, R3 = R each...Rtotal for left will be 2R...current will be low compared to the one on right whose Rtotal is R+(R2/(R+R))= 1.5R...so overal current is more....potential drop will be more across R1 compared to left....therefore potential difference A and B on left...will be more

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