Consider the network of four resistors shown in the diagram, where R 1 = 2.00? ,
ID: 1305406 • Letter: C
Question
Consider the network of four resistors shown in the diagram, where R1 = 2.00? , R2 = 5.00? , R3 = 1.00? , and R4 = 7.00? . The resistors are connected to a constant voltage of magnitude V. (Figure 1)
Part A
Find the equivalent resistance RA of the resistor network.
Express your answer in ohms.
Part B
Two resistors of resistance R5 = 3.00? and R6 = 3.00? are added to the network, and an additional resistor of resistance R7 = 3.00? is connected by a switch, as shown in the diagram..(Figure 2) Find the equivalent resistance RB of the new resistor network when the switch is open.
Express your answer in ohms.
Part C
Find the equivalent resistance RC of the resistor network described in Part B when the switch is closed.
Express your answer in ohms.
Figure 1Figure 2 of 2
Consider the network of four resistors shown in the diagram, where R1 = 2.00? , R2 = 5.00? , R3 = 1.00? , and R4 = 7.00? . The resistors are connected to a constant voltage of magnitude V. (Figure 1)
Part A
Find the equivalent resistance RA of the resistor network.
Express your answer in ohms.
RA = ?Part B
Two resistors of resistance R5 = 3.00? and R6 = 3.00? are added to the network, and an additional resistor of resistance R7 = 3.00? is connected by a switch, as shown in the diagram..(Figure 2) Find the equivalent resistance RB of the new resistor network when the switch is open.
Express your answer in ohms.
RB = ?Part C
Find the equivalent resistance RC of the resistor network described in Part B when the switch is closed.
Express your answer in ohms.
RC = ?Figure 1Figure 2 of 2
Explanation / Answer
The formula for calculating a total of n number of resistors wired in series is:
Req = R1 + R2 + .... Rn
That is, all the series resistor values are simply added.
equivalent resistance of resistors in parallel: 1 / R = 1 / R1 + 1 / R2 + 1 / R3 +...
part 1
Req = (5*2/(5+2) + 1 + 7)
=66/7 ohm
part 2
R eq = 5/2 + 1+ 10
=13.5 ohm
part 3
R eq = 5/2 + 1 + 2.1 + 3
=8.6 ohm