Please help! A two-turn circular wire loop of radius 0.733 m lies in a plane per
ID: 1307774 • Letter: P
Question
Please help!
A two-turn circular wire loop of radius 0.733 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.635 T. If the entire wire Ls reshaped from a two-turn circle to a one-turn circle in 0.102 s (while remaining in the same plane), what is the magnitude of the average induced emf epsioln in the wire during this time? Use Faradav's law In a model generator, a 570-turn rectangular coil 0.074 in In- 0.17 m rotates with an angular frequency of 12.6 rad/s in a uniform magnetic field of 0.53 T. What is the maximum end induced in the coil? An AC generator consists of 40 turns of wire with an area of 0.12 m2. The loop rotates in a magnetic field of 0.119 T at a constant frequency of 27.9 Hz. The generator is connected across a circuit load with a total resistance of 33 ft. Find the maximum emf induced by the generator. Find the maximum induced current. Answer in units of AExplanation / Answer
1.induced emf e = NBdA/dt
initail area A = pir^2 = 3.14* 0.733 * 0.733 = 1.687 m^2
when convterted into one turn , total length = 2*2*3.14* 0.733
L = 2pi r = 9.206 m
r = 9.206/2pi
r = 1.466 m
area A = 3.14* 1.466*1.466 = 6.748 m^2
so change of area = 6.748 -1.687 = 5.061 m^2
so now induced emf e = 5.061* 0.635/0.102
emf e = 31.50 volts
--------------------------------------------------
0.16:
induced emf e = NABW
e = 570* 0.074*0.17*12.6* 0.53
e = 47.88 volts
-----------------------------------------
0.17 :
induced emf e = NABW
W = 2pif
emf e = 40 * 0.12* 0.119 * *2*3.14* 27.9
emfe = 100.08 volts
---------------------------------------
induced current i = emf/R = 100.08/33 = 3.03 Amps
----------------------------------------------
---------------------------------------------------------------------------------------------
Feel free to COMMENT on this answer if u seek furthur more CLARIFICATION. Do Rate and Encourage Me to HELP you More.
HAPPY LEARNING @ CHEGG