An electron is accelerated through a potential difference of 10,000 volts and co

Question

An electron is accelerated through a potential difference of 10,000 volts and collides with a tungsten target. It is slowed by bremsstrahlung (braking radiation). Calculate both the kinetic energy of the electron just before it reaches the tungsten target and the maximum frequency X-ray that can be generated by the bremsstrahlung process. The KE is 10,000 eV and the maximum frequency is 2.4 times 1015 Hz The KE is 10,000 eV and the maximum frequency is 3.6 times 1018 Hz The KE is 10,000 eV and the maximum frequency is 2.4 times 1018 Hz The KE is 1.6 times 10-15 Joules and the maximum frequency is 3.6 times J O18 Hz The KE is 1.6 times 10-15 J and the maximum frequency is 3.6 times 1014 Hz

Explanation / Answer

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