Please help me solve the 4 highlighted questions. I provided all the aditional w
ID: 1313138 • Letter: P
Question
Please help me solve the 4 highlighted questions. I provided all the aditional work to help that I have donw so far as a background. The procedures are in the bottom right of the two pages becuase that is the only place it would fit.
Draw a diagram showing all the forces acting on the ruler when the distance GC = 4 cm and mark all the distances. Write an equation using f = 0 and label it equation 1 Equation _ 1 R-W-0.98N = 0 Take the torque of all the forces acting on the ruler about the point A when GC = 4. Form an equation using lx = 0 and label it equation 2. Solve equations 1 and 2 for the two unknown forces. What are the two unknown forces that you solved? Must solve for R and W -.5 middot W + .54 middot R - .98 middot D = 0 R-W-0.98N = 0 R=1.89mN. This value is the reactant force that is applied back on the pivot point of the ruler. W=91mN, This is the value of the force acting downwards upon the original pivot point of the ruler, also known as it center of gravity. Take the torque of all the forces acting on the ruler about the point B when GC = 4. Form an equation using Ex = 0 and label it equation 3. Solve equations 1 and 3 and solve for the two unknown forces. What are the two unknown forces that you solved? To begin, since the lab was done once again through a computer a conversion factor needed to be created to get the actual length of the objects that were used. The value given was 30cm and the value found was 6.5cm. These numbers were used in the conversion factor to give a multiplier of 4.62. After this, the center of gravity (G) was to be found by balancing the ruler on the pivot point. Its beginning center of gravity was in the middle at 50cm. Then the ruler was to be put a point C where CG = x = 4cm by suspending a mass of lOOg on point D. The position of the l00g mass was then varied until the ruler reached equilibrium again. This value was recorded as CD = d. These steps were repeated a total of 10 times, increasing the distance by 2cm. The time measure of the distance was still recorded as CD = d. The values of x and d were then examined. mass and distance x were then calculated. The conversion factor remained the same at 4.62. Draw a diagram showing the forces acting on the meter rule when it is in equilibrium for any value of m. Take the torque of these forces about G and obtain an equation using the condition 2x = 0 Write the equation in in the form y = mx. Identify the x and y variables and draw an appropriate graph. Measure the slope of the graph. In this experiment, a meter ruler was balanced at its center of gravity (G). Then a mass of 20g was suspended from point A 10cm away from the center of gravity. Then an unknown weight was suspended from the side of the ruler W. It was then balanced again at the center of gravity by changing the position of the unknown weight. The distance was measured from W to G and recorded as X. The mass was increased to 40g then by lOg intervals. The new weight caused the distance of x to be changed. The values of theExplanation / Answer
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