Please show work! Thank you Three linear polarizers are oriented as follows: The

Question

Please show work! Thank you

Three linear polarizers are oriented as follows: The axis of the second is at an angle of 59.0 degree relative to the first. The axis of the third is at an angle of 31.0 degree relative to the second, so the axis of the third polarizer is perpendicular to the axis of the first. Unpolarized light of intensity Io= 18.6 W/m2 is incident on the first polarizer. What is the intensity of the light after it passes through all three polarizers? What is the intensity oí the transmitted light if the second polarizer is removed?

Explanation / Answer

I will tell you the concept both a and b parts can be done in the same way

I is the intesity of light entering a liner polariswer and i be the intensity leaving it

i = I(cos^2(theta))

theta is angle made by the polariser sheet with the light direction of propagation

Apply this formula at every polairser as light passing through passess throug the other

Here assume that first angel i.e the angle made by the fist polaiser to be zero then theta for other polirizers is obtained by angle made by those polarisers with the first one

comment if you have any doubts

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