A doubly ionized molecule (I.e., a molecule lacking two electrons), moving in a

Question

A doubly ionized molecule (I.e., a molecule lacking two electrons), moving in a magnetic field, experiences a magnetic force of 6.22 x 10^-16 N as it moves at 205 m/s at 62.7 degrees to the direction of the field. Find the magnitude of the magnetic field.
Answer ___________ T A doubly ionized molecule (I.e., a molecule lacking two electrons), moving in a magnetic field, experiences a magnetic force of 6.22 x 10^-16 N as it moves at 205 m/s at 62.7 degrees to the direction of the field. Find the magnitude of the magnetic field.
Answer ___________ T
Answer ___________ T

Explanation / Answer

magnetic force on the particle is

F = Bq v sin ( theta )

6.22*10^ -16 N = B 2( 1.6*10^ -19 C ) (205 m/s) sin62.7)

B = 10.67 T

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