In the Figure, a block m1 sits on a table. There is static friction between bloc
ID: 1318743 • Letter: I
Question
In the Figure, a block m1 sits on a table. There is static friction between block and table. Block m2 hangs from a knot, as shown. Call the tension in the rope connecting the knot to m1, "T1". Call the tension in the rope connecting the knot to m2, "T2". Call the tension in the third rope (the one tipped up by an angle theta, connecting the knot to the wall), "T3". The system is in equilibrium.
In the previous problem, block m1 weighs 865 N. The coefficient of static friction between the block and the table is 0.27 and the angle theta is 30.0o. Find the maximum weight of block m2 for which block m1 will remain at rest.
Explanation / Answer
In the horizontal direction...
Friction = The horizontal component of T3
(.27)(865) = T3(cos 30)
T3 = 297 N
In the vertical, the weight of the mass will balance the vertical component of T3
mg = (297)(sin 30)
m2 = 134.8 N