In the figure below, R 1 = 6.50 ? and R 2 = R 3 = R 4 = 29.0 ?. The battery has
ID: 1319651 • Letter: I
Question
In the figure below, R1 = 6.50 ? and R2 = R3 = R4 = 29.0 ?. The battery has an emf of ? = 120 V.
a.) How much energy is dissipated by all four resistors in one minute?
J
(Hint: First, find the total power dissipated.)
b.) What are the current flowing through and voltage drop across R1?
I1 = A
V1 = V
Also, find the common voltage and current for each of the other resistors. Comment on how they would compare if these resistors did NOT happen to have the same resistance.
I2 = I3 = I4 = A, which ---Select--- happen to be equal since the resistances are equal will always be equal, even if the resistances were unequal n/a; not enough info .
V2 = V3 = V4 = V, which ---Select--- happen to be equal since the resistances are equal will always be equal, even if the resistances were unequal n/a; not enough info .
Explanation / Answer
a) Rnet = R1 + R2/3
= 6.5 + 29/3
= 16.17 ohms
Power dissipated = V^2/Rnet
= 120^2/(16.17)
= 890.54 Watts
Energy dissipated, E = P*t
= 890.54*60
= 53432.4 J
b) current thorugh R1,
I1 = V/Rnet
= 120/16.17
= 7.42 A
V1 = I1*R1
= 7.42*6.5
= 48.23 volts
c)
I2 = I3 = I4 = I1/3
= 7.42/3
= 2.47 A
d) v1 = v2 = v3 = V - v1
= 120 - 48.23
= 71.77 volts