A very light 1.6-m-long handle part is pushed down on the right side of the fulc
ID: 1320802 • Letter: A
Question
A very light 1.6-m-long handle part is pushed down on the right side of the fulcrum and a 0.050-m-long part on the left side supports the back of the car. How hard must you push down on the handle so that the lever exerts an 7900-N force to lift the back of the car?
A very light 1.6-m-long handle part is pushed down on the right side of the fulcrum and a 0.050-m-long part on the left side supports the back of the car. How hard must you push down on the handle so that the lever exerts an 7900-N force to lift the back of the car?Explanation / Answer
This is a torque problem. When you push the right side of the lever down, you are producing clockwise torque
Torque = F * d, d = 1.6
Torque = F * 1.6
Counter clockwise torque = 7900 * 0.05 = 395
F * 1.6 = 395
F = 395/1.6 = 246.875 N