The capacitor in (Figure below) is initially uncharged and the switch, in positi

Question

The capacitor in (Figure below) is initially uncharged and the switch, in position c, is not connected to either side of the circuit. The switch is now flipped to position a for 15ms ,then to position b for 15ms , and then brought back to position c. Suppose that E = 9V . What is the final potential difference across the capacitor?

The capacitor in (Figure below) is initially uncharged and the switch, in position c, is not connected to either side of the circuit. The switch is now flipped to position a for 15ms ,then to position b for 15ms , and then brought back to position c. Suppose that E = 9V . What is the final potential difference across the capacitor?

Explanation / Answer

For the charging portion...

V = Vo(1 - e-t/RC)

V = 9(1 - e-15 X 10-3/(150)(40 X 10-6))

V = 8.26 Volts

Then for the discharge

V = Voe-t/RC

V = (8.26)(e-15 X 10-3/(150)(40 X 10-6))

V = .678 V

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---