Refer to the Diagram Below A. Write the junction rule for the junction at the to
ID: 1322574 • Letter: R
Question
Refer to the Diagram Below
A. Write the junction rule for the junction at the top of the circuit according to the directions of the currents you have chosen. Clearly show the directions of these currents in the diagram on the right side. Label these currents; I1, I2, I3 such that they would go throught R1, R2, R3 respectively.
B. Write the 2 loop rules according to the diagram and the directions of your currents.
C. Use Kirchhoff's rules to determine the currents; I1, I2, and I3 through the respective resistors. You must explicitly show the calculaions for credit.
Refer to the Diagram Below A. Write the junction rule for the junction at the top of the circuit according to the directions of the currents you have chosen. Clearly show the directions of these currents in the diagram on the right side. Label these currents; I1, I2, I3 such that they would go through R1, R2, R3 respectively. B. Write the 2 loop rules according to the diagram and the directions of your currents. C. Use Kirchhoff's rules to determine the currents; I1, I2, and I3 through the respective resistors. You must explicitly show the calculations for credit.Explanation / Answer
A)
according to KCL law algbraic sum of currents entering and leaving equal to zero
or sum of entering currents equal to sum of leaving currents
assume that current flowing in resistor R1 is I1
current flowing in resistor R2 is I2
current flowing in resistor R3 is I3
AT THE JUNCTION POINT J
I1=I2+I3
B)
in this circuit it consists of two meshes
current flowing in mesh 1 is I1
current flowing in mesh 2 is I3
assume I1 is clockwise
assume I3 is clockwise
KVL equations
IN LOOP1
E1=E2+I1R1+I2R2
7=11+100I1+200I2
100I1+200I2=-4
IN LOOP2
E2+E3=(I3-I1)R2+I3R3=-I2R2+(I1-I2)R3=-500I2+300I1
24=-500I2+300I1?
SOLVE ABOVE EQUATIONS
C)
I1=0.025A
I2=-0.0327A
I3=0.0577A