In the circuit below, the capacitor is initially charged. It has capacitance of

Question

In the circuit below, the capacitor is initially charged. It has capacitance of 0.023F, while the resistor has resistance 47?. How long after the switch is closed does the voltage on the capacitor fall to 37% of its initial value?

A) 1.1s

B).000049s

C)121s

D)2043s

E)2.1s

In the circuit below, the capacitor is initially charged. It has capacitance of 0.023F, while the resistor has resistance 47?. How long after the switch is closed does the voltage on the capacitor fall to 37% of its initial value? A) 1.1s B).000049s C)121s D)2043s E)2.1s

Explanation / Answer

V/Vini = e-t/RC

ln(0.37) = -t/1.081

t=1.1 sec

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