In the construction industry, standard doors are specified by a four digit numbe
ID: 1322963 • Letter: I
Question
In the construction industry, standard doors are specified by a four digit number. The first two digits are the door's width, and the last two are the door's height (given in feet and inches). A 2868 door therefore has width L = 32" and h = 80".A 2868 door with mass m = 36kg stands closed in the angular position theta = 0. The door opens in the clockwise direction.
1.) calculate the torque on the door from the following forces applied to the closed door at the location specified. These torques cause the door to swing in the clockwise direction. A) F1 = -(14N)j applied at 4" from the hinge. (hint T1 = -r1F1)
B) F2 = (5N) In the construction industry, standard doors are specified by a four digit number. The first two digits are the door's width, and the last two are the door's height (given in feet and inches). A 2868 door therefore has width L = 32" and h = 80".
A 2868 door with mass m = 36kg stands closed in the angular position theta = 0. The door opens in the clockwise direction.
1.) calculate the torque on the door from the following forces applied to the closed door at the location specified. These torques cause the door to swing in the clockwise direction. A) F1 = -(14N)j applied at 4" from the hinge. (hint T1 = -r1F1)
B) F2 = (5N)
A 2868 door with mass m = 36kg stands closed in the angular position theta = 0. The door opens in the clockwise direction.
1.) calculate the torque on the door from the following forces applied to the closed door at the location specified. These torques cause the door to swing in the clockwise direction. A) F1 = -(14N)j applied at 4" from the hinge. (hint T1 = -r1F1)
B) F2 = (5N)
Explanation / Answer
1. Torque T = r x F
T = rF sin theta
here sin theta = L/R
sin theta = 32/80
s0
T = 14 * 4 * 0.4470 * (sin 32/80)
T = 0.174 Nm
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2. no torqu acts as point of application of force in the parallel to the direction of torque