Consider the system of capacitors shown in the figure below ( C 1 = 1.00 F, C 2

Question

Consider the system of capacitors shown in the figure below (C1 = 1.00 F, C2 = 7.00 F).

(a) Find the equivalent capacitance of the system.
F

(b) Find the charge on each capacitor.
C (on C1)
C (on C2)
C (on the 6.00 F capacitor)
C (on the 2.00 F capacitor)

(c) Find the potential difference across each capacitor.
V (across C1)
V (across C2)
V (across the 6.00 F capacitor)
V (across the 2.00 F capacitor)

(d) Find the total energy stored by the group.
mJ

Consider the system of capacitors shown in the figure below (C1 = 1.00 F, C2 = 7.00 F). (a) Find the equivalent capacitance of the system. F (b) Find the charge on each capacitor. C (on C1) C (on C2) C (on the 6.00 F capacitor) C (on the 2.00 F capacitor) (c) Find the potential difference across each capacitor. V (across C1) V (across C2) V (across the 6.00 1/2 F capacitor) V (across the 2.00 i 1/2 F capacitor) (d) Find the total energy stored by the group. mJ

Explanation / Answer

C1 AND 6 uF ARE IN SERIES SO

Ceq=1 + 6

Ceq= 7 micro farad

C2 and 2 uf are also in series so

Ceq(1)=2 + 7

Ceq(1)= 9 micro farad

now Ceq and Ceq(1) are in parallel

so

1/Ceq(final )=1/7 + 1/9

Ceq(final )=3.938 micro farad

total charge=c *v

Q=C V

Q=3.938 * 90

Q=354.47 ( total charge )

now u can easily calculate charge on each capacitor

c) the volatge will be divided 2 voltage each

d ) ) U =(1/2)CV^2 using this formula u can calculate energy

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