Consider the circuit of three identical batteries and three identical bulbs conn
ID: 1325013 • Letter: C
Question
Consider the circuit of three identical batteries and three identical bulbs connected exactly as shown here. In this problem, assume that each battery is a perfect physics battery supplying voltage V and the bulbs are perfect ohmic devices with resistance R. A friend of yours says. That middle battery is hooked up backwards! The bulbs won?t light if you hook the circuit up like that. (a) Respectfully and thoroughly explain to your friend that the bulbs will indeed light. In your explanation. use both math and conceptual understanding. Can you use the Ski - area analogy to help? (b) Find the power dissipated by each bulb and the total power dissipated by the circuit.Explanation / Answer
a) Math : Veq = V + (-V) + V = V , so it will light up .
There are 3 indentical batteries bulubs .one is in reverse but other two will make over all voltage difference
3 chair lifters and 3 skiers .
b) Req = R + R + R = 3R
V eq = V - V + V = V
I = Veq/Req = V/3R
Voltage across each resistor = I*R = V/3
c) Power dissipated by each bulb P1 = I^2*R = (V^2/9R^2) *R = V^2/9R
total power dissipated = 3*p1 = V^2/3R