Part A Find the direction of the magnetic field that will cause the electron to

Question

Part A

Find the direction of the magnetic field that will cause the electron to follow the semicircular path from A to B .

The magnetic field must go into the page.

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Correct

Part B

Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B . Use a radius of 4.65cm , not the 5cm given in the picture.

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Part C

Find the time required for the electron to move from A to B.

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Part D

Find the direction of the magnetic field, that would be needed if the particle were a proton instead of an electron?

The magnetic field must go out of the page.

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Correct

Part E

Find the magnitude of the magnetic field, that would be needed if the particle were a proton instead of an electron? It will go in the same path so have the same radius.

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Part F

What is the magnitude of the force the electron experiences from the magnetic field?

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Part G

What is the magnitude of the force the proton experiences from the magnetic field?

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Be = T An electron at point A in the figure (Figure 1) has a speed of 1.8110^6m/s . Part A Find the direction of the magnetic field that will cause the electron to follow the semicircular path from A to B . The magnetic field must go into the page. SubmitMy AnswersGive Up Correct Part B Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B . Use a radius of 4.65cm , not the 5cm given in the picture. SubmitMy AnswersGive Up Part C Find the time required for the electron to move from A to B. SubmitMy AnswersGive Up Part D Find the direction of the magnetic field, that would be needed if the particle were a proton instead of an electron? The magnetic field must go out of the page. SubmitMy AnswersGive Up Correct Part E Find the magnitude of the magnetic field, that would be needed if the particle were a proton instead of an electron? It will go in the same path so have the same radius. SubmitMy AnswersGive Up Part F What is the magnitude of the force the electron experiences from the magnetic field? SubmitMy AnswersGive Up Part G What is the magnitude of the force the proton experiences from the magnetic field? SubmitMy AnswersGive Up

Explanation / Answer

Part A

into the page

part B

r = (me*v)/(q*B)

B = (9.1*10^-31*1.81*10^6)/(1.6*10^-19*0.0465) = 0.00022138 T

C)

T = (2*pi*r)/v = (2*3.142*0.0465)/(1.81*10^6) = 1.614*10^-7 s

required time is T/2 = 8.07*10^-8 S

D) out of the page

E) r = (mp*v)/(q*B)

B = (1.67*10^-27*1.81*10^6)/(1.6*10^-19*0.0465) = 0.406 T

F) F = q*v*B = (1.6*10^-19*1.81*10^6*0.00022138) = 6.411*10^-17 N

G) F = q*v*B = (1.6*10^-19*1.81*10^6*0.406) = 1.175*10^-13 N

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