An 84-kg fireman slides 5.1 m down a fire pole. He holds the pole, which exerts

Question

An 84-kg fireman slides 5.1 m down a fire pole. He holds the pole, which exerts a 520-N steady resistive force on the fireman. At the bottom he slows to a stop in 0.48 m by bending his knees.

What can you determine using this information?

the acceleration of the fireman while stopping the height of the fireman the time it takes for the fireman to stop after reaching the ground the time it takes for the fireman to reach the ground the acceleration of the fireman while sliding down the pole the velocity of the fireman just before reaching the ground

Explanation / Answer

force = mass x acceleration

F = m a

a = F / m

= 520 / 84

= 6.19 m / s2

to get the time taken we use

s = u t + (1 / 2) a t2

u = 0

s = 5.1 m

to get the velocity we use

v = u + a t

where u = 0

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