Problem 4.8 Part C (r-2t2) m What is the particle\'s direction of motion, measur

Question

Problem 4.8 Part C (r-2t2) m What is the particle's direction of motion, measured as an angle from the x-axis, at t = 0 s ? A particle's trajectory is described by x = and y = (t2-2t) m, where t is ns. and y (t2 2t) m, where t is in s. Express your answer using two significant figures counterclockwise from the +x axis Submit My Answers Give Up Incorrect Try Again; 5 attempts remaining Part D What is the particle's direction of motion, measured as an angle from the x-axis, at t = 5.0s ? Express your answer using two significant figures counterclockwise from the +x axis Submit My Answers Give Up Incorrect Try Again; 5 attempts remaining

Explanation / Answer

C)

as Vx = dx/dt

VX = d/dt(0.5 t^3 - 2 t^2)

Vx = (1.5 t^2 - 4 t)

at t = 0 s

Vx = 0 m/s

Vy = dy/dt

Vy = d/dt(0.5 * t^2 - 2t)

Vy = t - 2

for t = 0

Vy = -2 m/s

Hence , theta = -90 degree

the particle's direction of motion is -90 degree

part D)

at t = 5 s

Vx = (1.5 * 5^2 - 4 * 5)

Vx = 17.5 m/s

Vy = 5 - 2

Vy = 3 m/s

theta = arctan(3/17.5)

theta = 9.73 degree

the direction of motion is 9.73 degree

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