a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.0
ID: 1327555 • Letter: A
Question
a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.0 blocks east. A) what is the magnitude of her resultant displacement?B) what is the total distance she travels? a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.0 blocks east. A) what is the magnitude of her resultant displacement?B) what is the total distance she travels? a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.0 blocks east. A) what is the magnitude of her resultant displacement?B) what is the total distance she travels?Explanation / Answer
a)
here
x components = -3 blocks , +6 blocks
y components = +4 blocks
the component of the resultants are
Rx = -3 + 6 = 3 blocks
Ry = 4 blocks
the magnitude and direction of the resultant are then given by
R = sqrt( Rx^2 + Ry^2)
R = sqrt( 3^2 + 4^2) = 5 blocks
then
theta = tan^-1(Ry / Rx) = 53.1 deg north of east
b)
the distance traveled is
d = (3 + 4+ 6 )blocks = 13 blocks