I need help with this homework please i have attached the graph as well. Hope th

Question

I need help with this homework please i have attached the graph as well. Hope the sizes are ok for you to see.

Thank you!

Ohm's Law Lab features of the Multimeter when measuring resistance, voltage, and current. (1) Using the Ohmmeter, determine the resistance of one resistor and record it in the table. You must (2) Design the circuit below using the 1.5 Volt battery and a resistor. Use the spring do this measurement when the resistor is not connected to the battery s on the circuit board to hold the wires in place Battery Resistor (3) Using the Voltmeter, determine the voltage across the resistor and record it in the table. (4) Using the Ammeter, determine the current in the circuit and record it in the table (5) Repeat steps 1 through 4 for each resistor Resistance () | Voltage (V) 2200-52 | | , -3 V 900 V 20052 | 1,43 21700 52 | 1.43 | Current (A) | 1/R (-1) 15 A | tol.ol 5 26 A 31 82 5 3 03.03 (6) Unhook the circuit and measure the EMF directly across the battery: 43 Consult the paper on how to graph data on Microsoft Excel to do the following steps (7) Using Excel, make a graph of the table with Current on the y-axis and Resistance on the x-axis. (8) Using Excel, make a graph of the table with Current on the y-axis and 1/R on the x-axis. (9) Determine the equation of the line which goes through the points in part (8). Have Excel place this equation on the graph. Have the instructor check these graphs before printing. Print both graphs so that both are on the same single sheet of paper and attach the graphs to this report (10) Using a very small resistor, measure its resistance with an ohmmeter. Connect it to the battery and measure the voltage across it with a voltmeter Resistance (0) Voltage (V) 22 bo SC | 1.43

Explanation / Answer

1)V=iR if we compare it with xy= constant it is a hyperbola equartion

here V is a constant,so we get downward curve.

2)y=mx+c represents equation of a straight line passing through the origin

in ohms law current is o y-axis and resistace(1/R)on x axis

just compare it with y=mx+c

we get slope=V=i/(1/R)

3)V=i/(1/R)

dv/v=(di/i )xdR/R

4)when no current flows through the battery teminal voltage is equal to emf

current is leaving(Discharging) from the cell,terminal voltage is less than the emf(V=E-ir)

current is entering(charging)into the cell.terminal voltage is greater than emf(V=E+ir)

5)i=net emf/total resistance

i=E/(R+r)

E=i(R+r)

=iR+ir

E=V+ir,here r is the internal resistance

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