Part A - What is the effective capacitance of the circuit? C e f f = C 2+( C 1 C

Question

Part A - What is the effective capacitance of the circuit?

  Ceff=C2+(C1C3/C1+C3)+C4  

Part B - What is the charge on C1?

Part C - What is the potential difference across C3?

  Ceff=C1+C2+(C3C4/C3+C4)   Ceff=C2+[C1(C3+C4/)C1+C3+C4]   Ceff=C1C2(C3+C4)+C2C3C4 / C1(C3+C4)+C2(C3+C4)+C3C4  

  Ceff=C2+(C1C3/C1+C3)+C4  

Part B - What is the charge on C1?

  QC1=V[(C1C3/C1+C3)+C4]   QC1=VC1     QC1=VC1(C3+C4) / C1+C2+C3     QC1=V[(C3C4C3+C4)+C1]

Part C - What is the potential difference across C3?

  V3=VC1 / C3+C4     V3=VC1(C3+C4) / C1+C2+C3     V3=VC1 / C1+C2+C3     V3=VC3     V3= V[(C1C3 / (C1+C3)(C3+C4)+(C4 / C3+C4) ]   V3=V(C3C4 / (C3+C4)^2 + C1/C3+C4)  

Explanation / Answer

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