Mapp Sapling Learning The Nat-glucose symport system of intestinal epithelial ce

Question

Mapp Sapling Learning The Nat-glucose symport system of intestinal epithelial cells couples the "downhill transport of two Na* ions into the cell to the "uphill" transport of glucose, pumping glucose into the cell against its concentration gradient. If the Na* concentration outside the cell (I[Na lout) is 147 mM and that inside the cell (INa'ln) is 19.0 mM, and the cell potential is -49.0 mV (inside negative), calculate the maximum ratio of [glucosein to [glucose]out that could theoretically be produced if the energy coupling were 100% efficient. Assume the temperature is 37 "C Number glucose], glucoselin glucose Jout -2.535 There is a hint available! View the hint by clicki bottom divider bar. Click on the ing on the divider bar again to hide the hint. Close

Explanation / Answer

The glucose and Na antiport transports one glucose and 2 Na ions across the cell membrane. It is called antiport because if one ion gets in another goes out. The formula to explain this reaction is as follows:
deltaG = RT ln [glucose in]/[glucose out] + 2 RT ln [Na in]/ [Na out] + 2 Fe

First calculate 2 RT ln [Na in]/ [Na out], then add 2 Fe
Use this Delta G in formula; deltaG = RT ln [glucose in]/[glucose out]

The R = 0.00814 Kj/mol
T = 273 +37 = 310K
F = 96.5Kj/mol
e = cell potential = -49mV
ln = natural logarithm

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