A deuteron particle (the nucleus of an isotope of hydrogen consisting of one pro

Question

A deuteron particle (the nucleus of an isotope of hydrogen consisting of one proton and one neutron and having a mass of 3.34×1027 kg ) moving horizontally enters a uniform, vertical, 0.640 Tmagnetic field and follows a circular arc of radius 56.0 cm .

a) How fast was this deuteron moving just before it entered the magnetic field ?

B) How fast was this deuteron moving just after it came out of the field?

c) What would be the radius of the arc followed by a proton that entered the field with the same velocity as the deuteron?

Explanation / Answer

a) qVB = mV^2 /r

V=qBr/m

V= 17192218.5811 m/s

r = mV/qB

B) same speed

c) qVb = mV^2 /r

same charge so same magnetic field but less mass (1/2)

so r = 28 cm

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