For the cylindrical system of conductors shown to the right, the central wire ca
ID: 1348275 • Letter: F
Question
For the cylindrical system of conductors shown to the right, the central wire carries a current I out of the page while the two outer conducting shells each carry I/ 3 into the page. Compute the magnetic field in region II between the two shells
(a) B~ II = µ0I 2?r counterclockwise
(b) B~ II = µ0I 3?r clockwise
(c) B~ II = µ0I 4? L~ × rˆ r 2 counterclockwise
(d) B~ II = 0
(e) B~ II = µ0I 6?r counterclockwise
(f) B~ II = µ0I 2?r clockwise
(g) B~ II = µ0I 3?r counterclockwise
(h) B~ II = 5µ0I 6?r counterclockwise
(i) B~ II = 5µ0I 6?r clockwise
Explanation / Answer
(g) B~ II = µ0I 3r counterclockwise
here There is no eggect of outer shell.
magnetic field due to straight wire, B_wire = mue*I/(2*pi*r) (counter closkwise)
magnetic field due to inner shell, B_innershell = mue*(I/3)/(2*pi*r) (clockwise)
Bnet = B_wire - B_ineershell
= mue*I/(2*pi*r) - mue*(I/3)/(2*pi*r)
= mue*I/(3*pi*r) (countercloclwise)