Question #1: The systems shown below are in equilibrium with m = 3.40 kg and = 3

Question

Question #1:

The systems shown below are in equilibrium with m = 3.40 kg and = 31.0°. If the spring scales are calibrated in newtons, what do they read? Ignore the masses of the pulleys and strings and assume the pulleys and the incline are frictionless.

scale in (a): ( ) N

scale in (b): ( ) N

scale in (c): ( ) N

scale in (d): ( ) N

Question #2:

A 2.90-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.30 m down the incline in 1.40 s.

(a) Find the magnitude of the acceleration of the block.
( ) m/s2

(b) Find the coefficient of kinetic friction between block and plane.

( )
(c) Find the friction force acting on the block.

'

---Select--- (up the incline - down the incline - normal to the incline and upward - normal to the incline and downward).

(d) Find the speed of the block after it has slid 2.30 m.
( ) m/s

'

---Select--- (up the incline - down the incline - normal to the incline and upward - normal to the incline and downward).

Explanation / Answer

1.)
(a)
Weight of both the masses are equal.
Therefore , F = mg - mg = 0
Scale in (a) - 0 N

(b)
Tension in the string = m*g
Therefore, F = 3*9.8 N
Scale in (b) - 29.4 N

(c)
Tension in the string = m*g + m*g
Therefore, F = 3*9.8 + 3*9.8 N
Scale in (c) - 58.8 N

(d)
Tension in the string = m*g sin(31)
Therefore, F = 3*9.8 * sin(31) N
Scale in (d) - 15.14 N

Please post seperate question in seperate post.

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