Part A You give the block on the table a push to the right so that it starts to

Question

Part A

You give the block on the table a push to the right so that it starts to move. If the magnitude of the frictional force exerted by the table on the block is half the magnitude of the gravitational force exerted on the hanging block, what is the acceleration of the hanging block after you have stopped pushing the block on the table?

Part B

What would this hanging-block acceleration be if you had pushed the block on the table to the left instead? Consider only a short time interval after you stop pushing.

Explanation / Answer

Here ,

part A)

mass of hanging block is m

for the block on table,

Frictional force , f = 0.5 * m * g

let the acceleration of a

Using second equation of motion

a = net force/total mass

a = (mg - 0.5 mg)/(2 m + m )

a = 0.167 * g

a = 0.167 * 9.8

a = 1.633 m/s^2

the acceleration of the hanging block is 1.633 m/s^2

part B)

Now, if the block is pushed to the left

a = net force/total mass

a = (mg + 0.5 mg)/(2 m + m )

a = 0.5 * g

a = 0.5 * 9.8

a = 4.9 m/s^2

the acceleration of the hanging block is 4.9 m/s^2

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