For that displacement, find the work done on the package by the machine\'s force

Question

For that displacement, find the work done on the package by the machine's force.

Find the average power of the machine's force on the package.

A machine carries a 3.5 kg package from an initial position of . For that displacement, find the work done on the package by the machine's force. Find the average power of the machine's force on the package. + (6.00 N) I vector + (4.00 N) F vector = (2.00 N) at t = 13 s. The constant force applied by the machine on the package is + (7.40 m) I vector I vector + (11.5 m) D vector f = (7.20 m) at t = 0 to a final position of + (0.20 m) I vector + (0.75 m) D vector i = (0.50 m)

Explanation / Answer

Mass, m = 4 kg

Force vector, F = (2.00 Ni + 4.00 Nj + 6.00 k) N

Displacement vector, S = df - di

                                    = ( 7.2 i + 11.5 j + 7.4 k ) - ( 0.5 i + 0.75 j + 0.2 k )

                                    = (6.7 i + 10.75 j + 7.2 k ) m

Work done, W = F.(df - di)

                        = ( 2.00 i + 4.00 j + 6.00 k ) . ( 6.7 i + 10.75 j + 7.2 k )

                        = 99.6 J

                        = 0.996x102 J

Average power on the package, = W/time interval = 99.6 J / 13 s - 0 s = 7.66 W

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