A small block with mass 0.0400kg is moving in the xy -plane. The net force on th

Question

A small block with mass 0.0400kg is moving in thexy-plane. The net force on the block is described by the potential- energy function U(x,y)= (5.95J/m2 )x2-(3.55J/m3 )y3.

Part A

What is the magnitude of the acceleration of the block when it is at the point x= 0.21m , y= 0.68m ?

Express your answer with the appropriate units.

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Part B

What is the direction of the acceleration of the block when it is at the point x= 0.21m , y= 0.68m ?

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A small block with mass 0.0400kg is moving in thexy-plane. The net force on the block is described by the potential- energy function U(x,y)= (5.95J/m2 )x2-(3.55J/m3 )y3.

Part A

What is the magnitude of the acceleration of the block when it is at the point x= 0.21m , y= 0.68m ?

Express your answer with the appropriate units.

a =

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Part B

What is the direction of the acceleration of the block when it is at the point x= 0.21m , y= 0.68m ?

? =   ? counterclockwise from the +x-axis

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Explanation / Answer

U(x,y)= (5.95 )x2-(3.55)y3

x= 0.21m , y= 0.68m

=0.262-1.116

=0.854

workdone=force required to move the block*distance

from the diagram calculate displacement

F=ma

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