Presented by UNIVERSITY PHYSICS Philip R. Kesten David L. Tauck sapling learning
ID: 1382332 • Letter: P
Question
Presented by UNIVERSITY PHYSICS Philip R. Kesten David L. Tauck sapling learning Find the magnitude and direction of the electric field produced by a red blood cell at the following locations Assume that red blood cells can be modeled as spheres of 7.03 um diameter with -2.55 x 102 C excess charge uniformly distributed over the surface. Inside the cell at a distance of 3.25 pm from the center. Number Just inside the surface of the cell. Number Just outside the surface of the cell. Number VI m. At a point outside the cell 3.25 um from the surface. Number VI mExplanation / Answer
Radius of the cell = d/2 = 7.03/2 = 3.515 micro m
1) Inside the cell, E = k*Q*r/R^2
= 9*10^9*2.55*10^-12*3.25*10^-6/(3.515*10^-6)^3
= 1.717*10^9 V/m <<<<<<<<<<<-------Answer
2) Just Inside the cell surface, E = k*Q*/R^2
= 9*10^9*2.55*10^-12/(3.515*10^-6)^2
= 1.857*10^9 V/m <<<<<<<<<<<-------Answer
3) same 1.857*10^9 V/m <<<<<<<<<<<-------Answer
4) at a point 3.25 micro m from the surface
r = 3.515 + 3.25
= 6.765 micro m
out side the sphere, E = k*Q/r^2
= 9*10^9*2.55*10^-12/(6.756*10^-6)^2
= 5.03*10^8 V/m <<<<<<<<<<<-------Answer