Question 15 of 15 Incorredt Incorrect Map presented by UNIVERSITY PHYSICS Philip

Question

Question 15 of 15 Incorredt Incorrect Map presented by UNIVERSITY PHYSICS Philip R. Kesten David L. Tauck sapling learning vpical human lens has an index of refraction of 1.430. The lens has a double convex shape, but its curvature can be varied by the ciliary muscles acting around its rim. At minimum power, the radius of the front of the lens is 10.0 mm while that of the back is 6.00 mm. At maximum power the radii are 6.50 mm and 5.50 mm, respectively If the lens were in air, what would be the maximum power and associated focal length of the lens? Number Number 144.3 diopters 6.92 x 10-3 Imm What would be the minimum power and associated focal length of the lens? Number Number 114.7 diopters 8.72x 10-3 At maximum power, how far behind the lens would the lens form an image of an object 15.5 cm in front of the front surface of the lens? Number Tools 10 Previous e Check Answer PreviousCheck Answe Next Next Exit Hint

Explanation / Answer

last part :

apply power P = 1/f in meter

so

f = 1/P = 1/114.7 = 0.00871m or   0.87 cm

u = 15.5 cm

so v = ?

use 1/f = 1/u +1/v

1/v = 1/f - 1/u

v = uf/(u-f)

v = 15.5 * 0.87/(15.5- 0.87)

v = 0.92 cm ---------------<<<<<<<<<<Answer

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