A small block is attached to an ideal spring and is moving in SHM on a horizonta

Question

A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the amplitude of the motion is 0.090m , it takes the block 2.64sto travel from x= 0.090m to x= -0.090m .

Part A

If the amplitude is doubled, to 0.180m , how long does it take the block to travel from x= 0.180m to x= -0.180m ?

Express your answer to two significant figures and include the appropriate units.

Part B

If the amplitude is doubled, to 0.180m , how long does it take the block to travel from x= 0.090m to x= -0.090m ?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

A) Time period is T = 2*pi*sqrt(m/K)

here K is the spring constant

and m is the attached mass

time period does not depend upon the Amplitude

so the answer for part A) is if amplitude is doubled also ,the time taken from x = 0.18 m to x = -0.18 m is 2.64 S

B) here the amplitude is 0.18m

so the time taken fro -A/2 to +A/2 is (2*2.64)/3 = 1.76 S

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