Part 1: At the second dark fringe on the screen (position y on the screen), find

Question

Part 1:

At the second dark fringe on the screen (position y on the screen), find a) the corresponding path length difference, in terms of lambda, and b) the phase shift, in terms of pi.

Part 2:

Using the small angle approximation (? = sin ? = tan ?), if the distance from the central bright region to the second dark fringe is y, what is the wavelength of the light, in terms of d, L, and y?

A screen is illuminated by monochromatic light whose wave length is lembda, as shown. The distance from the slits to the screen is L.

Explanation / Answer

y = nLambda D/d defines bright fringes

1st dark fringe y1 = 3/2 LAMBDA D/d

2nd dark fringe y2= 5/2 LAMBDA D/d

LAMBDA = 2PIE

SO 5/2 LAMBDA = 5pie

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---