QUESTION Suppose in a given photoelectric experiment the frequency of light is l

Question

QUESTION Suppose in a given photoelectric experiment the frequency of light is larger than the cutoff frequency. If delta Vs is the stopping potential and e the electron charge, the magnitude of e delta Vs is then equal to: (Select all that apply.) the difference between the photon energy and the work function. the energy of the incident photons. the work function. the maximum kinetic energy of emitted electrons. Review the discussion of the stopping potential. Examine how it is related to the photon energy and work function as also discussed in connection with the equation below. KEmax = hf - phi

Explanation / Answer

As you can see from the formula

KEmax = hf - phi

Here, phi = e [delta Vs].

Thus, it is the

A. The difference between the photon energy and the work function

D. The maximum kinetic energy of the emitted electrons

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