Please don\'t post answer if it is wrong. Light enters a solid tube made of plas
ID: 1389721 • Letter: P
Question
Please don't post answer if it is wrong.
Light enters a solid tube made of plastic having an index of refraction of 1.61. The light travels parallel to the upper part of the tube. (See the figure (Figure 1).) You want to cut the face AB so that all the light will reflect back into the tube after it first strikes that face. What is the largest that theta can be if the tube is in air? Theta max1 = degree If the tube is immersed in water of refractive index 1.333, what is the largest that theta can be? Theta max2 = degreeExplanation / Answer
1)
sin(C)=u1/u2
=1/1.61
sin(C)=1/1.61
====>
C=38.39
thet1=90-C
=90-38.39
=51.6 degrees
2)
sin(C)=u1/u2
=1.333/1.61
sin(C)=1.333/1.61
====>
C=55.88
thet1=90-C
=90-55.88
=34.11 degrees