Hi I am having trouble on my homework, and would appreciate this problem done. T
ID: 1391726 • Letter: H
Question
Hi I am having trouble on my homework, and would appreciate this problem done. Thanks!
2) To the right is shown a parallel plate capacitor with area A and gap d. Inside the capacitor there is a uniform magnetic field H as shown. A charged particle of mass m and charge q traveling at a velocity y enters the capacitor. (a) What magnitude of voltage should be applied to the capacitor to have the particle travel in a straight line9 (b) How can such a device be used to determine the energy of an electron? (c) How can this be used as part of a system to determine the mass of a particle?Explanation / Answer
Given that,
charge on the particle = q ; its mass = m, magntiude of B fiedl = H , velocity of the particle = v
Area of the plate = A and seperation = d
we know that the magnetic force experienced by particle will be
F(magnetic) = q v H
and electric force will be F(electric) = V/d
these forces must be balancing each other for the particle to follow a straight path
F(magnetic) = F (electric)
q v H = V / d
V = q v H x d
Hence the Volate = V = q v d H
(b) When the particle is accelerated usring the particle accelerator, because of the favorable conditions provided, the kinetic eenergy of the particle becomes much larger than the equivalent mass energy, so much havier particles than the original used can be produced.
(c)[mass is unkown most of the time]
Due to the presence of magnetic field, thre occus the deflection in the original path of the particle. The magnetic force provides the centripital force. So,
F(magnetic) = F(centripital)
q v B = m v2 / r
m = q B / v r