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The figure shows a 0.3 kg baseball just before and just after it collides with a

ID: 1393542 • Letter: T

Question

The figure shows a 0.3 kg baseball just before and just after it collides with a bat. Just before, the ball has velocity v 1 of magnitude 11.0 m/s and angle e1 31.8 Just after, it is traveling directly upward with velocity v 2 of magnitude 9.00 m/s. The duration of the collision is 1.20 ms. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the impulse on the ball from the bat? What are the (c) magnitude and (d) direction of the average force on the ball from the bat?

Explanation / Answer

A)
Impulse in x direction, Jx = m*(v2x - v1x)

= 0.3*(0 - (-11*cos(31.8) )

= 2.8 N.s

Impulse in y direction, Jy = m*(v2y - v1y)

= 0.3*(9 - (-11*sin(31.8) )

= 4.44 N.s

so, |J| = sqrt(Jx^2 + Jy^2)

= sqrt(2.8^2 + 4.44^2)

= 5.25 N.s
b) direction, theta = tan^-1(Jy/Jx)

= tan^-1(4.44/2.8)

= 57.7 degrees

c) imaulse, J = F*t

==> F = J/t

= 5.25/(1.2*10^-3)

= 4375 N

d) direction : same 57.7 degrees with +x axis