A sit to-stand model divides the body into three segments: calves, thighs, and t
ID: 1397306 • Letter: A
Question
A sit to-stand model divides the body into three segments: calves, thighs, and trunk. The first table shows the marker coordinates at the point of maximum knee extension torque, and the second table shows relative segment center of mass (COM) locations: Marker Ankle 0.111 0.081 Knee 0.245 0.423 Hip -0.049 0.663 0.184 1.142 Suprasternale Segment COM location Relative mass (proportion of length) (proportion) Calf 0.421 from knee to ankle 0.108 Thigh 0.403 from hip to knee 0.258 0.634 Trunk 0.441 from suprasternale to hip a) What is the calf segment center of mass? A. calf 0.166 m, calf 0.223 m. B. calf 0.177 m, calf, 0.251 m. C. calf 0.188 m, calf, 0.279 m. D. calf 0.230 m, calf, 0.385 m. b) What is the thigh segment center of mass? A. thighx 0.026 m, thighy 0.599 m B. thigh, 0.069 m, thighy 0.566 m C. thighx 0.097 m, thighy 0.542 m D. thigh, 0.126 m, thighy 0.518 m c) What is the trunk segment center of mass? A. trunks 0.035 m, trunk 0.837 m. B. trunk 0.052 m, trunk 0.872 m. C. trunkx 0.067 m, trunk 0.899 m. D. trunks 0.081 m, trunk 0.930 m. d) What is the overall body center of mass? A. COM 0.083 m, COM 0.711 m. B. COM 0.089 m, COM 0.766 m. C. COM 0.114 m, COM 0.565 m. D. COM 0.120 m, COM 0.766 m. e) What is the angular position of this individual's ankle joint and hip.joint? A. ankle dorsiflexion and hip extension B. ankle dorsiflexion and hip flexion C. ankle plantar flexion and hip extension D. ankle plantar flexion and hip flexionExplanation / Answer
a)
C.
b)
D. thighx=0.126m, thighy=0.518m
c)
B.
d)
A.
e)
B.