Please show steps: 1.How does the motion of the particles of the medium differ b
ID: 1409719 • Letter: P
Question
Please show steps:
1.How does the motion of the particles of the medium differ between transverse and longitudinal waves? Explain.
2. For each of the following, calculate the frequency, in hertz, and the period, in seconds:
1)a bee beating its wings 3000 times in 30 s.
2)a tuning fork completing 2048 oscillations in 8.0 s.
3. The engine of a Grand Prix race car sounds different as it approaches you than when it is moving away from you. Explain why.
4. As a boat moves through a lake creates it creates waves which emanate outward from its motor. If the frequency of the source is 0.37 Hz and the wave speed is 2.50 m/s, find the distance between adjacent wave crests.
Explanation / Answer
1 ans
The motion of particles of medium difference b/w transverse wave and longitudinal wave
In transverse wave ;
If the direction of propagation of the waves is perpendicular to the direction of vibration of the particles the waves are said to be transverse waves
Properties:
A crest and a trough make up a complete wave
The distance b/w two successive crest(or) troughs
Is equal to wavelength
All particles of the medium execute S.H.M with same amplitude ,time period and frequency
Transverse waves can propagate only in solids and on the surface of liquid
Longitudinal waves :
If particles of the medium vibrate parallel to the direction of propagation of the waves the waves are said to be longitudinal waves
Properties:
The distance b/w any two successive compressions or rarefactions is equal to wavelength of wave
A compression and rarefaction make up a complete wave
All the particles of the medium execute S.H.M with same amplitude time period and frequency
Longitudinal waves can travel trough solids liquid and in gas well
2 and
The relation b/w frequency and time is f=n/T
Where T=time period , n= no.of oscillation
Now we solve two points
(1) given => n=3000
Time period T=30 s
Therefore the frequency f=3000/30=100 Hz
(2) given => n=2048
Time period T=8 s
Therefore the frequency =2048/8
The frequency =256 Hz
(3) ans
The engine moving away from you the frequency change is occurred do to the cause of Doppler effect
The appreant frequency is low as we compare the original frequency
(4) ans
Frequency of the source f=0.37 Hz
Wavespeed v=2.5 m/s
This concept belongs to waves
According to frequency of waves in lake => f=V/wavelength
0.37=2.5/wavelength
Therefore the distance b/w adjacent wave crests=2.5/0.37
The distance =6.8 m