Student A is working on spring potential energy experiment on uniform oscillatio
ID: 1416980 • Letter: S
Question
Student A is working on spring potential energy experiment on uniform oscillation motion,he created Force (y-axis) vs position (x-axis) graph, calculated the slope function and area under initial and final position. Here is some of the data he collected.
Slope equation = 2.113x+0.759
Area under F vs X graph between X1-X2 = 1.172
T1 = Time(s) = 1.35, Position (m)= 0
T2 = Time(s) = 1.52, Position (m)= 0.75
a- According to data, please calculate Spring Potential Energy change between X1 to X2.
b- Calculate percent error based on given numbers.
Explanation / Answer
We know that the slope of the force position graph gives the spring constant
F= kx
K = 2.113 N/m
E = 1/2kx^2 = 0.6 J
The Error in the K value is at X= 0 , i.e. = 0.759
Hence
E = .21 J
Hence the Error will be around 32 %