Consider an \"average\" electron (q = -e) in the silver wire. a) How far does it
ID: 1417986 • Letter: C
Question
Consider an "average" electron (q = -e) in the silver wire. a) How far does it drift between collisions? Is this drift with or against the field direction? How do you know? b) What difference of potential (Delta V) does it cross? Is it positive or negative and how do you know? How much kinetic energy does it gain? (The numbers here are extremely small.) c) If the wire has a diameter of 0.5 mm and it is 0.6 m long, how many conduction electrons does it contain? d) Determine the total kinetic energy gained by all of the conduction electrons in between each collision? This, according to the Dude model (see text), is how much thermal energy they transfer to the atoms in the wire per collision cycle. Use this result to determine the rate (in Watts) that thermal energy is developed in the wire? (This is the Joule heating rate.)Explanation / Answer
a) far does it drift = 5.013 * 10-8 m
Itz against field direction .
b) potential difference = 0.5 V
It is positive potential difference .
=> kinetic energy = 1.6 * 10-19 * 0.5
= 8 * 10-20 J
c) conduction electrons it contain = 8.13 * 1015
d) Total kinetic energy = 8.13 * 1015 * 8 * 10-20
= 6.504 * 10-4 J
Rate of thermal energy = 6.504 * 10-4/0.04
= 0.01626 W