You are testing the null hvpothesis that the outcome of a dihybrid cross conform

Question

You are testing the null hvpothesis that the outcome of a dihybrid cross conforms to a 1:1:1:1 ratio resulting from a cross between a heterozygous individual (AaBb) and a homozygous recessive individual (aabb), and that any differences are due to chance. Your calculated value is 5.721. Do you reject or fail o reject your nul bypohes7 Asume a sigfof0065 O Reject, because the x value is greater than the critical value O Fail to reject, because the x value is less than the critical value. O Reject, because the x value is is less than the critical value. O Fail to reject, because the x value is greater than the critical value

Explanation / Answer

The correct choice should be

At o<0.05, for three degrees of freedom, the critical value is 7.815

Given, chi square value is less than critical value. Thus we fail to reject null hypothesis.

Fail to reject because chi square value is less than the critical value.

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