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The colors you see in soap films are due to the interference effect. Assume that

ID: 1418452 • Letter: T

Question

The colors you see in soap films are due to the interference effect. Assume that the interference effect is mainly due to the water molecules (index 1.33). Consider a 450nm thick soap film. Upon reflection, what wavelength(s) of visible light will destructively interfere? Upon reflection, what wavelength(s) of visible light will constructively interfere? As the water evaporates, the film will decrease in thickness. After a few minutes the thickness has dropped to l00nm. How do your answers change for a) and b)?

Explanation / Answer

2nt = ( m+1/2) lamda

lamda = t 4n/ ( 2 m+1)

= 450 nm ( 4( 1.33)/ 2( 0) + 1)

=2394 nm

lamda = t 4n/ ( 2 m+1)

= 450 nm ( 4( 1.33)/ 2( 1) + 1)

=798nm

lamda = t 4n/ ( 2 m+1)

= 450 nm ( 4( 1.33)/ 2( 2) + 1)

=478.8nm

lamda = t 4n/ ( 2 m+1)

= 450 nm ( 4( 1.33)/ 2( 3) + 1)

=342nm

construtive interference occurs 478.8 nm

distructive intereference condition is

2nt = m lamda

lamda = 2nt/ m

m = 1

lamda = 2(1.33) ( 450 nm)

=1197 nm

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(c)

lamda = t 4n/ ( 2 m+1)

= 100 nm ( 4( 1.33)/ 2( 0) + 1)

=532 nm

lamda = t 4n/ ( 2 m+1)

= 100 nm ( 4( 1.33)/ 2( 1) + 1)

=177.33

construtive interference occurs 177.33 nm

lamda = 2nt/ m

m = 1

lamda = 2(1.33) ( 100 nm)

=266 nm

m=  2(1.33) ( 100 nm) /2

=133 nm

m=  2(1.33) ( 100 nm) /3

=88.66 nm

m=  2(1.33) ( 100 nm) /4

=66.5 nm

distrucitive interference occurs 133 nm,88.66 nm,66.5 nm, ........